The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
Text Solution
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I N = Current in N-type semiconductor
I P = Current in P-type semiconductor
Now N e = N h and n e = n h
Also, 
and 
Were,
N e = electron concentration in N-type
N h = Hole concentration P-type
&N e = N h
n h = hole concentration in N-type
n e = Electron concentration P- type
Since, 
and N e > n e
From this we can conclude that, I N > I P
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